771_jewels_and_stone
Leetcode 771 Link to heading
You're given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".
Example 1:
Input: J = "aA", S = "aAAbbbb"
Output: 3
Example 2:
Input: J = "z", S = "ZZ"
Output: 0
My solution -
func numJewelsInStones(J string, S string) int {
stoneMap := make(map[string]int)
for _,i := range(S) {
stoneMap[string(i)] += 1
}
ret := 0
for _,i:= range(J) {
ret += stoneMap[string(i)]
}
return ret
}